Tianyancha - online database of companies, organization. This website is the 7450th most popular in the global Wikipedia ranking of websites and the 619th most popular website in Chinese Wikipedia. Article “天眼查” in Chinese Wikipedia has 35.1 points for quality (as of July 1, 2025). The article contains 12 references and 4 sections.
Since the creation of article “天眼查”, its content was written by 16 registered users of Chinese Wikipedia and edited by 16 registered Wikipedia users in all languages.
Tianyancha is on the 619th place in local ranking of websites in Chinese Wikipedia and on the 7450th place in global ranking of websites in all the time.
The article is cited 58 times in Chinese Wikipedia and cited 58 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | Chinese: #25927 01.2022 |
Global: #555855 01.2022 |
| Best Rank | Chinese: #21132 11.2021 |
Global: #1045692 11.2021 |
On 16 March 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: 98th Academy Awards, Michael B. Jordan, Sinners, Jessie Buckley, Paul Thomas Anderson, Sean Penn, One Battle After Another, Amy Madigan, Hamnet, Timothée Chalamet.
In Chinese Wikipedia the most popular articles on that day were: 逐玉, 2026年世界棒球經典賽, 一戰再戰, 第98屆奧斯卡金像獎, 臥底嬌娃, 李海銅, 张凌赫, 世界棒球經典賽, 罪人 (2025年電影), 2026年伊朗戰爭.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(14.8+11.88+33.33+33.33+82.17)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
