Libev - high-performance software library that implements an event loop. This software is the 9111th most popular in the global Wikipedia ranking of software. Article “Libev” in Chinese Wikipedia has 25.2 points for quality (as of July 1, 2025). The article contains 8 references and 3 sections.
Since the creation of article “Libev”, its content was written by 3 registered users of Chinese Wikipedia and edited by 3 registered Wikipedia users in all languages.
Libev is on the 9111th place in global ranking of software on Wikipedia in all the time.
The article is cited 2 times in Chinese Wikipedia and cited 2 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | Chinese: #147300 03.2024 |
Global: #2294573 03.2024 |
| Best Rank | Chinese: #21968 02.2021 |
Global: #1040382 02.2021 |
On 16 March 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: 98th Academy Awards, Michael B. Jordan, Sinners, Jessie Buckley, Paul Thomas Anderson, Sean Penn, One Battle After Another, Amy Madigan, Hamnet, Timothée Chalamet.
In Chinese Wikipedia the most popular articles on that day were: 逐玉, 2026年世界棒球經典賽, 一戰再戰, 第98屆奧斯卡金像獎, 臥底嬌娃, 李海銅, 张凌赫, 世界棒球經典賽, 罪人 (2025年電影), 2026年伊朗戰爭.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(9.74+7.92+0+25+83.25)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
