Article "Tôi là Hoa hậu Hoàn vũ Việt Nam" in Vietnamese Wikipedia has 15.4 points for quality (as of November 1, 2023). The article contains 4 references and 9 sections. The article also contains quality flaw template, which reduce quality score.
Since the creation of article "Tôi là Hoa hậu Hoàn vũ Việt Nam", its content was written by 22 registered users of Vietnamese Wikipedia and edited by 22 registered Wikipedia users in all languages.
The article is cited 16 times in Vietnamese Wikipedia and cited 16 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from November 1, 2023 (including revision history and pageviews for previous years).
| Best Rank | Vietnamese: #10775 06.2022 |
Global: #1283071 06.2022 |
On 22 May 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: Ademola Lookman, Atalanta BC, Toni Kroos, Gian Piero Gasperini, Bayer 04 Leverkusen, international recognition of the State of Palestine, UEFA Europa League, Ebrahim Raisi, State of Palestine, YouTube.
In Vietnamese Wikipedia the most popular articles on that day were: Đài Truyền hình Kỹ thuật số VTC, Tô Lâm, Trần Quốc Tỏ, Trần Đại Quang, Chủ tịch nước Cộng hòa xã hội chủ nghĩa Việt Nam, Phan Đình Trạc, Bộ trưởng Bộ Công an (Việt Nam), Lương Tam Quang, Nguyễn Phú Trọng, Bộ Công an (Việt Nam).
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from November, 2023. When calculating current popularity and AI of articles data from October 2023 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(24.12+2.4+0+45+9.58)-0.81$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
