Article "Khu di tích Chiến thắng Tầm Vu" in Vietnamese Wikipedia has 16.5 points for quality (as of November 1, 2023). The article contains 6 references and 4 sections.
Since the creation of article "Khu di tích Chiến thắng Tầm Vu", its content was written by 2 registered users of Vietnamese Wikipedia and edited by 2 registered Wikipedia users in all languages.
The article is cited 3 times in Vietnamese Wikipedia and cited 3 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from November 1, 2023 (including revision history and pageviews for previous years).
| Best Rank | Vietnamese: #5917 10.2019 |
Global: #784791 10.2019 |
| Best Rank | Vietnamese: #21405 09.2017 |
Global: #2057780 03.2014 |
On 12 August 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: 2024 Summer Olympics, Olympic Games, 2028 Summer Olympics, Tom Cruise, Deadpool & Wolverine, Stephen Curry, Imane Khelif, All-time Olympic Games medal table, Snoop Dogg, list of Olympic Games host cities.
In Vietnamese Wikipedia the most popular articles on that day were: Cục An ninh chính trị nội bộ (Việt Nam), Đài Truyền hình Kỹ thuật số VTC, Đinh Văn Nơi, Tô Lâm, Xung đột biên giới Thái Lan-Campuchia 2009, Phạm Thế Tùng, Vũ Hồng Văn, Bộ Công an (Việt Nam), Nội chiến Myanmar, Nguyễn Ngọc Lâm.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from November, 2023. When calculating current popularity and AI of articles data from October 2023 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(11.26+3.59+16.67+20+30.77)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
