Likit Ruk Karm Duang Dao - 2019 Thai serie. This television series is the 95th most popular in Thai Wikipedia. Article "ลิขิตรักข้ามดวงดาว" in Thai Wikipedia has 16.9 points for quality (as of November 1, 2023). The article contains 9 references and 4 sections.
Since the creation of article "ลิขิตรักข้ามดวงดาว", its content was written by 24 registered users of Thai Wikipedia (8264th place) and edited by 24 registered Wikipedia users in all languages.
Likit Ruk Karm Duang Dao is on the 95th place in local ranking of television series on Thai Wikipedia in all the time.
The article is cited 38 times in Thai Wikipedia and cited 38 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from November 1, 2023 (including revision history and pageviews for previous years).
| Best Rank | Thai: #26 09.2019 |
Global: #49244 09.2019 |
On 23 April 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: YouTube, Serie A, Shōgun, Fallout, Facebook, Fallout, Saint George, Saint George Day, Inter Milan, ChatGPT.
In Thai Wikipedia the most popular articles on that day were: องค์การกระจายเสียงและแพร่ภาพสาธารณะแห่งประเทศไทย, พรนับพัน พรเพ็ญพิพัฒน์, ดวงใจเทวพรหม (ละครโทรทัศน์), อสมท, พิเศษ:ค้นหา, สโมสรฟุตบอลอาร์เซนอล, วชิรวิชญ์ ชีวอารี, ภาวะโลกร้อน, ประเทศไทย, สโมสรฟุตบอลเชลซี.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from November, 2023. When calculating current popularity and AI of articles data from October 2023 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(18.55+7.96+0+19.05+39.02)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
