Article "Средства массовой информации Воронежа" in Russian Wikipedia has 18.5 points for quality (as of November 1, 2023). The article contains 6 references and 7 sections.
Since the creation of article "Средства массовой информации Воронежа", its content was written by 20 registered users of Russian Wikipedia and edited by 20 registered Wikipedia users in all languages.
The article is cited 3 times in Russian Wikipedia and cited 3 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from November 1, 2023 (including revision history and pageviews for previous years).
| Best Rank | Russian: #402623 04.2022 |
Global: #3640390 04.2022 |
| Best Rank | Russian: #1056 04.2016 |
Global: #79348 04.2016 |
On 22 May 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: Ademola Lookman, Atalanta BC, Toni Kroos, Gian Piero Gasperini, Bayer 04 Leverkusen, international recognition of the State of Palestine, UEFA Europa League, Ebrahim Raisi, State of Palestine, YouTube.
In Russian Wikipedia the most popular articles on that day were: Яндекс, YouTube, Годовщины свадьбы, Новая Каледония, Раиси, Ибрахим, Государство Палестина, Международно-правовой статус Государства Палестина, Ходорковский, Михаил Борисович, Усик, Александр Александрович, Аталанта (футбольный клуб).
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from November, 2023. When calculating current popularity and AI of articles data from October 2023 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(6.91+3.3+0+35+47.47)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
