Alexander Trubetskoy - Russian prince and army officer. Article "Трубецкой, Александр Васильевич" in Russian Wikipedia has 21.2 points for quality (as of July 1, 2025). The article contains 10 references and 6 sections.
Since the creation of article "Трубецкой, Александр Васильевич", its content was written by 13 registered users of Russian Wikipedia and edited by 13 registered Wikipedia users in all languages.
The article is cited 25 times in Russian Wikipedia and cited 25 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | Russian: #70051 11.2014 |
Global: #611683 11.2014 |
| Best Rank | Russian: #8660 08.2013 |
Global: #271268 08.2013 |
On 9 July 2025 in multilingual Wikipedia, Internet users most often read articles on the following topics: João Pedro Junqueira de Jesus, Belinda Bencic, 2025 FIFA Club World Cup, Flavio Cobolli, Ozzy Osbourne, Superman, Mirra Andreeva, Diogo Jota, Novak Djokovic, Christian Horner.
In Russian Wikipedia the most popular articles on that day were: Яндекс, Старовойт, Роман Владимирович, Игра в кальмара (3-й сезон), Список умерших в 2025 году, Игра в кальмара, IMGSRC.RU, Кехман, Владимир Абрамович, Жуан Педро (футболист, 2001), Клубный чемпионат мира по футболу 2025, Россия.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(12.86+5.46+15.38+30+42.29)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
