Article "Стефан (Бех)" in Russian Wikipedia has 17.5 points for quality (as of August 1, 2024). The article contains 8 references and 5 sections.
In July 2024 the article "Стефан (Бех)" was edited by 1 authors in Russian Wikipedia and written by 1 authors in all languages.
Since the creation of article "Стефан (Бех)", its content was written by 18 registered users of Russian Wikipedia and edited by 18 registered Wikipedia users in all languages.
The article is cited 30 times in Russian Wikipedia and cited 30 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from August 1, 2024 (including revision history and pageviews for previous years).
| Best Rank | Russian: #163442 03.2008 |
Global: #3567701 03.2008 |
| Best Rank | Russian: #17922 06.2019 |
Global: #503683 02.2011 |
On 2 June 2025 in multilingual Wikipedia, Internet users most often read articles on the following topics: Karol Nawrocki, 2025 Polish presidential election, Alexander Bublik, Luis Enrique, Tupolev Tu-95, 2025 FIFA Club World Cup, Loïs Boisson, Désiré Doué, Mount Etna, Paris Saint-Germain FC.
In Russian Wikipedia the most popular articles on that day were: Яндекс, Операция «Паутина», Ту-95, УВБ-76, Навроцкий, Кароль Тадеуш, Мединский, Владимир Ростиславович, Ту-160, Ту-22М, ЯRUS, Пахмутова, Александра Николаевна.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from August, 2024. When calculating current popularity and AI of articles data from July 2024 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(11.19+4.4+7.69+25+39.21)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
