Kipchakovo - village in Korablinsky District, Russia. Article “Кипчаково (Рязанская область)” in Russian Wikipedia has 20 points for quality (as of July 1, 2025). The article contains 4 references and 7 sections.
Since the creation of article “Кипчаково (Рязанская область)”, its content was written by 5 registered users of Russian Wikipedia and edited by 5 registered Wikipedia users in all languages.
The article is cited 123 times in Russian Wikipedia and cited 123 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | Russian: #436279 08.2014 |
Global: #4734039 07.2016 |
| Best Rank | Russian: #35268 07.2023 |
Global: #854752 06.2014 |
On 26 September 2025 in multilingual Wikipedia, Internet users most often read articles on the following topics: Claudia Cardinale, One Battle After Another, ChatGPT, Alice in Borderland, Guinness, deaths in 2025, Benjamin Netanyahu, Assata Shakur, Charlie Kirk, Arthur Guinness.
In Russian Wikipedia the most popular articles on that day were: Кеосаян, Тигран Эдмондович, Яндекс, Симоньян, Маргарита Симоновна, Хмельницкая, Алёна Александровна, Кеосаян, Эдмонд Гарегинович, Кеосаян, Лаура Давидовна, Чигиринский, Шалва Павлович, Геворкян, Лаура Ашотовна, IMGSRC.RU, Список умерших в 2025 году.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(9.72+2.19+30.77+35+22.38)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
