SPYSEE - Oma Co., Ltd. website. This website is the 7570th most popular in the global Wikipedia ranking of websites and the 755th most popular website in Japanese Wikipedia. Article “SPYSEE” in Japanese Wikipedia has 20.3 points for quality (as of July 1, 2025). The article contains 10 references and 4 sections.
Since the creation of article “SPYSEE”, its content was written by 12 registered users of Japanese Wikipedia and edited by 12 registered Wikipedia users in all languages.
SPYSEE is on the 755th place in local ranking of websites in Japanese Wikipedia and on the 7570th place in global ranking of websites in all the time.
The article is cited 6 times in Japanese Wikipedia and cited 6 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | Japanese: #105253 05.2011 |
Global: #694690 05.2011 |
| Best Rank | Japanese: #6057 11.2010 |
Global: #274555 11.2010 |
On 16 March 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: 98th Academy Awards, Michael B. Jordan, Sinners, Jessie Buckley, Paul Thomas Anderson, Sean Penn, One Battle After Another, Amy Madigan, Hamnet, Timothée Chalamet.
In Japanese Wikipedia the most popular articles on that day were: 小泉八雲, 同志社国際中学校・高等学校, 若嶋津六夫, 伊藤大海 (野球), 高橋成美, 井端弘和, 太田裕二, ワールド・ベースボール・クラシック, 高田みづえ, 尾崎将司.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(4.5+3.61+0+12.9+80.35)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
