Polese da Fabriano - semi-legendary figure of the reportedly first paper manufacturer in Italy, active in Bologna ca. 1150-1200. Article "Polese da Fabriano" in Italian Wikipedia has 15 points for quality (as of August 1, 2024). The article contains 3 references and 5 sections.
Since the creation of article "Polese da Fabriano", its content was written by 15 registered users of Italian Wikipedia and edited by 15 registered Wikipedia users in all languages.
The article is cited 7 times in Italian Wikipedia and cited 7 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from August 1, 2024 (including revision history and pageviews for previous years).
| Best Rank | Italian: #304941 10.2009 |
Global: #3753334 10.2009 |
| Best Rank | Italian: #22773 02.2023 |
Global: #726529 11.2013 |
On 12 March 2025 in multilingual Wikipedia, Internet users most often read articles on the following topics: Elon Musk, 2024–25 UEFA Champions League, UEFA Champions League, Diego Simeone, Kim Sae-ron, Kim Soo-hyun, Greenland, Giuliano Simeone, Donald Trump, ChatGPT.
In Italian Wikipedia the most popular articles on that day were: Delitto di Garlasco, Giuliano Simeone, Diego Simeone, Mare fuori, Groenlandia, Il Gattopardo, Oriana Fallaci, Episodi di Mare fuori (quarta stagione), Giovanni Simeone, Spike Lee.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from August, 2024. When calculating current popularity and AI of articles data from July 2024 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(3.73+1.81+0+21.74+47.52)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
