Gregorio De Lauro - Italian monk. Article “Gregorio De Lauro” in Italian Wikipedia has 12.2 points for quality (as of July 1, 2025). The article contains 5 references and 3 sections. The article also contains templates indicating quality issues, therefore its score was reduced by 0.64 points.
Since the creation of article “Gregorio De Lauro”, its content was written by 21 registered users of Italian Wikipedia and edited by 21 registered Wikipedia users in all languages.
The article is cited 6 times in Italian Wikipedia and cited 6 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | Italian: #245248 06.2014 |
Global: #3666850 06.2014 |
On 10 March 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: Iran, Mojtaba Khamenei, Enhypen, Ali Khamenei, Strait of Hormuz, Jeffrey Epstein, 2026 Iran war, 2026 World Baseball Classic, Donald Trump, World Baseball Classic.
In Italian Wikipedia the most popular articles on that day were: Le libere donne, Giusi Bartolozzi, Mario Tobino, Guerrieri - La regola dell'equilibrio, Le libere donne di Magliano, Episodi di Mare fuori (sesta stagione), One Piece (serie televisiva), Daniele Scardina, Storia d'inverno, Rai.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(7.04+2.96+0+13.04+41.34)-0.64$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
