A Plea for Vegetarianism and Other Essays - 1886 edition. Article "Difesa del vegetarianismo" in Italian Wikipedia has 19.9 points for quality (as of August 1, 2024). The article contains 5 references and 6 sections.
Since the creation of article "Difesa del vegetarianismo", its content was written by 9 registered users of Italian Wikipedia and edited by 9 registered Wikipedia users in all languages.
The article is cited 3 times in Italian Wikipedia and cited 3 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from August 1, 2024 (including revision history and pageviews for previous years).
| Best Rank | Italian: #544646 02.2009 |
Global: #5698860 02.2009 |
| Best Rank | Italian: #4656 10.2018 |
Global: #194712 10.2018 |
On 26 December 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: Squid Game, Boxing Day, 2004 Indian Ocean earthquake, Squid Game, season 2, Hanukkah, Azerbaijan Airlines Flight 8243, Empress Elisabeth of Austria, Nosferatu, Mufasa: The Lion King, Gladiator II.
In Italian Wikipedia the most popular articles on that day were: Il conte di Montecristo, Squid Game, Natale in casa Cupiello, Diamanti (film 2024), Stefano protomartire, Cast Away, Mufasa - Il re leone, Conclave (film), Giubileo universale della Chiesa cattolica, Il conte di Montecristo (miniserie televisiva 2025).
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from August, 2024. When calculating current popularity and AI of articles data from July 2024 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(4.49+3.01+0+26.09+65.79)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
