Unicode characters from E6000 to E6FFF codepoints - Wikimedia list article. Article "Table des caractères Unicode (E6000-E6FFF)" in French Wikipedia has 2.5 points for quality (as of November 1, 2023). The article contains 0 references and 3 sections.
Since the creation of article "Table des caractères Unicode (E6000-E6FFF)", its content was written by 3 registered users of French Wikipedia and edited by 3 registered Wikipedia users in all languages.
The article is cited 44 times in French Wikipedia and cited 44 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from November 1, 2023 (including revision history and pageviews for previous years).
| Best Rank | French: #509285 07.2008 |
Global: #3712736 07.2008 |
| Best Rank | French: #97861 10.2014 |
Global: #869956 05.2006 |
On 23 April 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: YouTube, Serie A, Shōgun, Fallout, Facebook, Fallout, Saint George, Saint George Day, Inter Milan, ChatGPT.
In French Wikipedia the most popular articles on that day were: Saison 1 de Secret Story, Kendji Girac, Cookie (informatique), Stillwater (film), Sabine Azéma, André Dussollier, Secret Story, Mouloudia Club d'Alger (football), YouTube, Saison 12 de Secret Story.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from November, 2023. When calculating current popularity and AI of articles data from October 2023 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(1.06+0+0+11.54+0)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
