Frederick William Fairholt - English antiquarian and wood engraver. Article "Frederick William Fairholt" in English Wikipedia has 15.9 points for quality (as of November 1, 2023). The article contains 1 references and 7 sections. The article also contains quality flaw template, which reduce quality score.
Since the creation of article "Frederick William Fairholt", its content was written by 27 registered users of English Wikipedia and edited by 27 registered Wikipedia users in all languages.
The article is cited 25 times in English Wikipedia and cited 25 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from November 1, 2023 (including revision history and pageviews for previous years).
| Best Rank | English: #1189377 04.2010 |
Global: #1760446 04.2010 |
| Best Rank | English: #14579 08.2003 |
Global: #24323 08.2003 |
On 28 April 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: YouTube, Fallout, Facebook, Baby Reindeer, Challengers, Premier League, Fallout, deaths in 2024, Queen of Tears, Arsenal F.C..
In English Wikipedia the most popular articles on that day were: Indian Premier League, Richard Gadd, Baby Reindeer, Challengers (film), Next Indian general election, Queen of Tears, Fallout (2024 TV series), Colin Jost, YouTube, 2024 Indian Premier League.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from November, 2023. When calculating current popularity and AI of articles data from October 2023 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(8.27+0.83+14.29+50+10.28)-0.84$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
