1998–99 Crewe Alexandra F.C. season - season of football team. Article "1998–99 Crewe Alexandra F.C. season" in English Wikipedia has 21 points for quality (as of August 1, 2024). The article contains 2 references and 10 sections.
Since the creation of article "1998–99 Crewe Alexandra F.C. season", its content was written by 10 registered users of English Wikipedia and edited by 10 registered Wikipedia users in all languages.
The article is cited 165 times in English Wikipedia and cited 165 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from August 1, 2024 (including revision history and pageviews for previous years).
| Best Rank | English: #2355498 03.2014 |
Global: #4065640 04.2015 |
| Best Rank | English: #301256 05.2018 |
Global: #664912 03.2014 |
On 13 April 2025 in multilingual Wikipedia, Internet users most often read articles on the following topics: Palm Sunday, Black Mirror, Rory McIlroy, ChatGPT, Alexander Volkanovski, A Minecraft Movie, Paddy Pimblett, Adolescence, list of Black Mirror episodes, Diego Lopes.
In English Wikipedia the most popular articles on that day were: Rory McIlroy, Justin Rose, Bryson DeChambeau, List of Masters Tournament champions, Grand Slam (golf), UFC 314, Kyren Lacy, Paddy Pimblett, Jaat (film), 1989 Tiananmen Square protests and massacre.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from August, 2024. When calculating current popularity and AI of articles data from July 2024 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(25.54+1.64+0+71.43+6.61)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
