Protestant Church Zeuchfeld - church building in Freyburg (Unstrut), Burgenlandkreis, Saxony-Anhalt, Germany. Article “Kirche Zeuchfeld” in German Wikipedia has 16.3 points for quality (as of July 1, 2026). The article contains 2 references and 5 sections.
Since the creation of article “Kirche Zeuchfeld”, its content was written by 6 registered users of German Wikipedia and edited by 6 registered Wikipedia users in all languages.
The article is cited 4 times in German Wikipedia and cited 4 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2026 (including revision history and pageviews for previous years).
| Best Rank | German: #816699 09.2025 |
Global: #6590872 09.2025 |
| Best Rank | German: #22130 08.2025 |
Global: #366093 08.2025 |
On 1 July 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: 2026 FIFA World Cup, Kylian Mbappé, Erling Haaland, Democratic Republic of the Congo, FIFA World Cup, Harry Kane, Romelu Lukaku, Senegal, Michael Olise, Sadio Mané.
In German Wikipedia the most popular articles on that day were: Demokratische Republik Kongo, Fußball-Weltmeisterschaft 2026, Senegal, Julian Nagelsmann, Erling Haaland, Sadio Mané, Fußball-Weltmeisterschaft 1994, Jürgen Klopp, Fußball-Europameisterschaft 2028, Fußball-Weltmeisterschaft.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 50 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2026. When calculating current popularity and AI of articles data from June 2026 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2026... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(8.16+2.74+13.33+23.81+33.47)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
