Alejandro Cavanna - association football player. Article “Alejandro Cavanna” in German Wikipedia has 25.1 points for quality (as of July 1, 2025). The article contains 7 references and 2 sections.
Since the creation of article “Alejandro Cavanna”, its content was written by 6 registered users of German Wikipedia and edited by 6 registered Wikipedia users in all languages.
The article is cited 5 times in German Wikipedia and cited 5 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | German: #365697 01.2017 |
Global: #2689769 01.2017 |
| Best Rank | German: #67197 12.2020 |
Global: #748732 12.2020 |
On 21 February 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: Jeffrey Epstein, Alysa Liu, Eric Dane, 2026 Winter Olympics, Rebecca Gayheart, Johannes Høsflot Klæbo, Wuthering Heights, amyotrophic lateral sclerosis, Andrew Mountbatten-Windsor, John F. Kennedy Jr..
In German Wikipedia the most popular articles on that day were: Eric Dane, Franziska Preuß, Jeffrey Epstein, Medaillenspiegel der Olympischen Winterspiele 2026, Laura Nolte, Dorothea Wierer, Andreas Hofer, Alysa Liu, Olympische Winterspiele 2026, Mariama Jamanka.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(5.75+10+0+9.52+100)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
