Faaborg Museum - art museum in Denmark. Article “Faaborg Museum” in Danish Wikipedia has 30.6 points for quality (as of July 1, 2025). The article contains 5 references and 6 sections.
Since the creation of article “Faaborg Museum”, its content was written by 21 registered users of Danish Wikipedia and edited by 21 registered Wikipedia users in all languages.
Faaborg Museum is on the 692nd place in local ranking of buildings on Danish Wikipedia in all the time.
The article is cited 53 times in Danish Wikipedia and cited 53 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | Danish: #9947 09.2019 |
Global: #1998538 09.2019 |
On 28 January 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: 2025–26 UEFA Champions League, Nipah virus, Doomsday Clock, UEFA Champions League, Elena Rybakina, Donald Trump, 2026 European Men's Handball Championship, killing of Alex Pretti, Kristi Noem, deaths in 2026.
In Danish Wikipedia the most popular articles on that day were: EM i håndbold 2026 (mænd), Mads Mensah Larsen, EM i håndbold (mænd), Jóhan á Plógv Hansen, Nikolaj Jacobsen, Danmarks håndboldlandshold (herrer), Thomas Arnoldsen, Ditte Giese, Mathias Gidsel, VM i håndbold (mænd).
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(8.57+3.47+87.5+20.69+32.7)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
