Article "Стефан Чакъров" in Bulgarian Wikipedia has 24.7 points for quality (as of August 1, 2024). The article contains 8 references and 2 sections.
In July 2024 the article "Стефан Чакъров" was edited by 2 authors in Bulgarian Wikipedia (1506th place) and written by 2 authors in all languages.
Since the creation of article "Стефан Чакъров", its content was written by 7 registered users of Bulgarian Wikipedia and edited by 7 registered Wikipedia users in all languages.
The article is cited 12 times in Bulgarian Wikipedia and cited 12 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from August 1, 2024 (including revision history and pageviews for previous years).
| Best Rank | Bulgarian: #46799 05.2010 |
Global: #5252600 05.2010 |
| Best Rank | Bulgarian: #1506 07.2024 |
Global: #521523 07.2024 |
On 13 April 2025 in multilingual Wikipedia, Internet users most often read articles on the following topics: Palm Sunday, Black Mirror, Rory McIlroy, ChatGPT, Alexander Volkanovski, A Minecraft Movie, Paddy Pimblett, Adolescence, list of Black Mirror episodes, Diego Lopes.
In Bulgarian Wikipedia the most popular articles on that day were: Цветница, Георги Христов (певец), Недялка Керанова, Лепа Брена, Звездомир Керемидчиев, Долорес О’Риърдън, Любо Киров, Мими Николова, Лазаровден, Като две капки вода.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from August, 2024. When calculating current popularity and AI of articles data from July 2024 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(3.61+10.13+0+9.52+100)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
