Darvo bez koren - 1974 film by Christo Christov. Article "Дърво без корен" in Bulgarian Wikipedia has 9.6 points for quality (as of August 1, 2024). The article contains 1 references and 5 sections.
Since the creation of article "Дърво без корен", its content was written by 10 registered users of Bulgarian Wikipedia and edited by 10 registered Wikipedia users in all languages.
Darvo bez koren is on the 317th place in local ranking of films on Bulgarian Wikipedia in all the time.
The article is cited 31 times in Bulgarian Wikipedia and cited 31 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from August 1, 2024 (including revision history and pageviews for previous years).
| Best Rank | Bulgarian: #922 06.2022 |
Global: #562677 06.2020 |
| Best Rank | Bulgarian: #1428 11.2020 |
Global: #516732 12.2018 |
On 26 December 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: Squid Game, Boxing Day, 2004 Indian Ocean earthquake, Squid Game, season 2, Hanukkah, Azerbaijan Airlines Flight 8243, Empress Elisabeth of Austria, Nosferatu, Mufasa: The Lion King, Gladiator II.
In Bulgarian Wikipedia the most popular articles on that day were: Валентина Терешкова, Ден на бащата, Братя Аргирови, Стефановден, Поколение Y, Лонгирбюен, Дан Колов, Маколи Кълкин, Кенгурови, Сам вкъщи.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from August, 2024. When calculating current popularity and AI of articles data from July 2024 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(7.9+1.27+0+23.81+14.85)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
