Article "Партрэт мастака М. Філіповіча" in Belarusian Wikipedia has 18.6 points for quality (as of November 1, 2023). The article contains 3 references and 2 sections.
Since the creation of article "Партрэт мастака М. Філіповіча", its content was written by 1 registered users of Belarusian Wikipedia and edited by 1 registered Wikipedia users in all languages.
Партрэт мастака М. Філіповіча is on the 253rd place in local ranking of paintings on Belarusian Wikipedia in all the time.
The article is cited 1 times in Belarusian Wikipedia and cited 1 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from November 1, 2023 (including revision history and pageviews for previous years).
| Best Rank | Belarusian: #11030 09.2017 |
Global: #8159113 09.2017 |
| Best Rank | Belarusian: #6224 10.2016 |
Global: #1070298 10.2016 |
On 25 June 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: UEFA Euro 2024, Julian Assange, UEFA European Championship, UEFA Euro 2020, Shifty Shellshock, 2024 Copa América, WikiLeaks, YouTube, Inside Out 2, House of the Dragon.
In Belarusian Wikipedia the most popular articles on that day were: Карлес Пучдэмон, Купалле, Васіль Быкаў, Другая сусветная вайна, Беларусь, УННВ, Вікіпедыя, Вольга Славаміраўна Бондарава, Спіс беларускіх імён, Расія.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from November, 2023. When calculating current popularity and AI of articles data from October 2023 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(1.81+1.42+5.26+8+76.51)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
