Article "Кабьер, Габриелла Ольга" in Russian Wikipedia has 43.7 points for quality (as of August 1, 2024). The article contains 71 references and 5 sections.
In July 2024 the article "Кабьер, Габриелла Ольга" was edited by 2 authors in Russian Wikipedia and written by 2 authors in all languages.
Since the creation of article "Кабьер, Габриелла Ольга", its content was written by 9 registered users of Russian Wikipedia and edited by 9 registered Wikipedia users in all languages.
The article is cited 4 times in Russian Wikipedia and cited 4 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from August 1, 2024 (including revision history and pageviews for previous years).
| Best Rank | Russian: #141135 02.2022 |
Global: #1348440 02.2022 |
| Best Rank | Russian: #2807 02.2022 |
Global: #159973 02.2022 |
On 8 December 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: Bashar al-Assad, Syria, Syrian civil war, Hafez al-Assad, Asma al-Assad, Hay'at Tahrir al-Sham, Abu Mohammad al-Julani, Alawites, flag of Syria, Ayrton Senna.
In Russian Wikipedia the most popular articles on that day were: Асад, Башар, Сирия, Яндекс, Фрейндлих, Алиса Бруновна, Гражданская война в Сирии, Асад, Хафез, Асад, Асма, Наступление сирийской оппозиции (2024), Хайят Тахрир аш-Шам, Сирийская оппозиция.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from August, 2024. When calculating current popularity and AI of articles data from July 2024 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(38.97+39.01+15.38+25+99.96)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
