Wikipedia tiếng Việt

VI

WikiRank.net
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Wikipedia tiếng Việt

Article "Wikipedia tiếng Việt" in Vietnamese Wikipedia has 62.1211 points for quality and 100 points for popularity. The article contains, among others metrics, 50 references and 9 sections.

In this language version of Wikipedia the article has the best quality. Also, this article is the most popular in that language version.
VI
31st place in the rating of Vietnamese Wikipedia.

There are 46 language versions for this article in WikiRank database (of the considered 55 Wikipedia language editions).

Data as of March 1, 2019. Query time 1.1293 sec.

The table below shows the language versions of the article with the highest quality.

Languages with the highest quality

#LanguageQuality gradeQuality score
1Vietnamese
Wikipedia tiếng Việt
62.1211
2English
Vietnamese Wikipedia
47.0034
3Hebrew
ויקיפדיה הווייטנאמית
40.3393
4Catalan
Viquipèdia en vietnamita
37.8014
5Simple English
Vietnamese Wikipedia
36.7464

The following table shows the most popular language versions of the article.

The most popular languages

#LanguagePopularity gradePopularity score
1Vietnamese
Wikipedia tiếng Việt
100
2English
Vietnamese Wikipedia
8.2609
3German
Vietnamesischsprachige Wikipedia
3.8076
4Russian
Вьетнамская Википедия
3.3845
5Japanese
ベトナム語版ウィキペディア
0.7163

Scores

Quality:
Relative popularity among languages:

Interwiki

AR: ويكيبيديا الفيتناميةAZ: Vyetnamca VikipediyaBE: В’етнамская ВікіпедыяBG: Уикипедия на виетнамски езикCA: Viquipèdia en vietnamitaCS: Vietnamská WikipedieDA: Vietnamesisk WikipediaDE: Vietnamesischsprachige WikipediaEL: Βιετναμέζικη ΒικιπαίδειαEN: Vietnamese WikipediaEO: Vjetnamlingva VikipedioES: Wikipedia en vietnamitaEU: Vietnamerazko WikipediaFA: ویکی‌پدیای ویتنامیFI: Vietnaminkielinen WikipediaFR: Wikipédia en vietnamienHE: ויקיפדיה הווייטנאמיתHI: वियतनामी विकिपीडियाHR: Wikipedija na vijetnamskom jezikuHU: Vietnámi WikipédiaHY: Վիետնամերեն ՎիքիպեդիաID: Wikipedia bahasa VietnamIT: Wikipedia in vietnamitaJA: ベトナム語版ウィキペディアKA: ვიეტნამური ვიკიპედიაKK: Вьетнамша УикипедияKO: 베트남어 위키백과MS: Wikipedia Bahasa VietnamNL: Vietnamese WikipediaPL: Wikipedia wietnamskojęzycznaPT: Wikipédia em vietnamitaRO: Wikipedia în vietnamezăRU: Вьетнамская ВикипедияSH: Vijetnamska WikipedijaSIMPLE: Vietnamese WikipediaSR: Википедија на вијетнамском језикуSV: Vietnamesiskspråkiga WikipediaTA: வியட்னாமிய விக்கிப்பீடியாTH: วิกิพีเดียภาษาเวียดนามTR: Vietnamca VikipediUK: В'єтнамська ВікіпедіяUZ: Vyetnamcha VikipediyaVI: Wikipedia tiếng ViệtVO: Vükiped VietnamänapükikZH: 越南語維基百科ZHMINNAN: O̍at-lâm-bûn Wikipedia

Popularity rank history

Normalized quality metrics

Languages comparsion

Cumulative results

About WikiRank

The project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 38 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from March, 2019. When calculating popularity, view statistics of articles for last month (February 2019) were taken into account.

You can also visit WikiRank.Live (previous version of the main tool), which can calculate quality and popularity based on current versions of Wikipedia articles in 7 languages.

It's planned to add different improvements to the project (such as adding to the analysis not only new quantitative characteristics, but also qualitative). In addition, it is planned to add estimates using machine learning algorithms and artificial intelligence, as well as based on the results of user comparison of specific multilingual information (for example, the WikiBest project). Please leave your comments and suggestions

More information about quality assessment of Wikipedia articles and project WikiRank can be found in scientific publications:

Additional information about quality issues can be found on Wikipedia Quality portal.

WikiRank video

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2015-2019, WikiRank.net

Quality and popularity formulas for the article Wikipedia tiếng Việt VI

$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(30.73+35.97+100+43.9+100)$$

where:

$$Popularity={tp(l)}/{tp(l^'_{tp})}×50+{sp(l)}/{sp(l^'_{sp})}×50=7937/7937×50+307/307×50$$

where:

The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas