จักรพรรดินีเอลิซาเบธแห่งรัสเซีย

TH

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จักรพรรดินีเอลิซาเบธแห่งรัสเซีย

Article "จักรพรรดินีเอลิซาเบธแห่งรัสเซีย" in Thai Wikipedia has 23.4763 points for quality and 0.1711 points for popularity. The article contains, among others metrics, 3 references and 2 sections. The article also contains quality flaw template, which reduce quality score.

This article has the best quality in English Wikipedia. However, the most popular language version of this article is Russian.

There are 49 language versions for this article in WikiRank database (of the considered 55 Wikipedia language editions).

Data as of July 1, 2018. Query time 0.0571 sec.

The table below shows the language versions of the article with the highest quality.

Languages with the highest quality

#LanguageQuality gradeQuality score
1English
Elizabeth of Russia
93.4738
2Spanish
Isabel I de Rusia
67.334
3Russian
Елизавета Петровна
64.1037
4Portuguese
Isabel da Rússia
64.0885
5Indonesian
Yelizaveta dari Rusia
52.0886

The following table shows the most popular language versions of the article.

The most popular languages

#LanguagePopularity gradePopularity score
1Russian
Елизавета Петровна
100
2English
Elizabeth of Russia
51.5335
3German
Elisabeth (Russland)
9.7849
4Japanese
エリザヴェータ (ロシア皇帝)
5.8407
5Polish
Elżbieta Romanowa
5.7713

Scores

Quality:
Popularity:

Interwiki

AR: إليزابيث إمبراطورة روسياAZ: Yelizaveta PetrovnaBE: Лізавета ПятроўнаBG: Елисавета (Русия)CA: Elisabet I de RússiaCS: Alžběta PetrovnaDA: Elisabeth af RuslandDE: Elisabeth (Russland)EL: Ελισάβετ της ΡωσίαςEN: Elizabeth of RussiaEO: Elizabeto (Rusio)ES: Isabel I de RusiaET: Jelizaveta PetrovnaEU: Elisabet I.a ErrusiakoaFA: امپراتریس الیزابتFI: Elisabet (Venäjä)FR: Élisabeth Ire (impératrice de Russie)GL: Isabel I de RusiaHE: יליזבטה, קיסרית רוסיהHR: Elizabeta, ruska caricaHU: Erzsébet orosz cárnőHY: Ելիզավետա ՊետրովնաID: Yelizaveta dari RusiaIT: Elisabetta di RussiaJA: エリザヴェータ (ロシア皇帝)KA: ელისაბედ I (რუსეთი)KK: Елизавета ПетровнаKO: 옐리자베타 페트로브나LA: Elisabetha (imperatrix Russiae)LT: JelizavetaNL: Elisabeth van RuslandNN: Elisabet av RusslandNO: Elisabeth av RusslandPL: Elżbieta RomanowaPT: Isabel da RússiaRO: Elisabeta a RusieiRU: Елизавета ПетровнаSH: Elizabeta, ruska caricaSK: Alžbeta I. (Rusko)SL: Elizabeta RuskaSR: Јелисавета I ПетровнаSV: Elisabet av RysslandTA: எலிசவேத்தா பெட்ரோவ்னாTH: จักรพรรดินีเอลิซาเบธแห่งรัสเซียTR: YelizavetaUK: Єлизавета ПетрівнаUZ: Yelizaveta PetrovnaVI: Elizaveta của NgaZH: 伊丽莎白·彼得罗芙娜·罗曼诺娃

Normalized quality metrics

Languages comparsion

Cumulative results

About WikiRank

The project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 37 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2018. When calculating popularity, view statistics of articles for last year (from 1 July 2017 to 30 June 2018) were taken into account.

You can also visit WikiRank.Live (previous version of the main tool), which can calculate quality and popularity based on current versions of Wikipedia articles in 7 languages.

It's planned to add different improvements to the project (such as adding to the analysis not only new quantitative characteristics, but also qualitative). In addition, it is planned to add estimates using machine learning algorithms and artificial intelligence, as well as based on the results of user comparison of specific multilingual information (for example, the WikiBest project). Please leave your comments and suggestions

The WikiRank project was developed on the basis of researches made by scientists from Poland and Belarus. More information about quality assessment of Wikipedia articles and project WikiRank can be found in scientific publications:

Additional information about quality issues can be found on Wikipedia Quality portal.

WikiRank video

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2015-2018, WikiRank.net

Quality and popularity formulas for the article จักรพรรดินีเอลิซาเบธแห่งรัสเซีย TH

$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(4.96+3.3+50+9.09+56.21)-0.67$$

where:

$$Popularity={tp(l)}/{tp(l^'_{tp})}×50+{sp(l)}/{sp(l^'_{sp})}×50=658/326810×50+1/710×50$$

where:

The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas