James I of England

SIMPLE

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James I of England

Article "James I of England" in Simple English Wikipedia has 13.7856 points for quality and 7.4083 points for popularity.

This article has the best quality in Greek Wikipedia. However, the most popular language version of this article is English.
418th place in the multilingual rating of people.
SIM
85th place in the rating of Simple English Wikipedia.
1285th place in the multilingual rating of all topics.

There are 52 language versions for this article in WikiRank database (of the considered 55 Wikipedia language editions).

Data as of March 1, 2019. Query time 0.7139 sec.

The table below shows the language versions of the article with the highest quality.

Languages with the highest quality

#LanguageQuality gradeQuality score
1Greek
Ιάκωβος Α΄ και ΣΤ΄ της Αγγλίας και της Σκωτίας
100
2Indonesian
James Charles Stuart
100
3Portuguese
Jaime VI da Escócia e I de Inglaterra
99.7162
4English
James VI and I
99.198
5Esperanto
Jakobo la 1-a (Anglio)
97.8947

The following table shows the most popular language versions of the article.

The most popular languages

#LanguagePopularity gradePopularity score
1English
James VI and I
100
2Russian
Яков I (король Англии)
16.9279
3French
Jacques VI et Ier
11.8477
4Spanish
Jacobo I de Inglaterra y VI de Escocia
11.6159
5German
Jakob I. (England)
10.1601

Scores

Quality:
Relative popularity among languages:

Interwiki

AR: جيمس السادس والأولAZ: I CeymsBE: Якаў I (кароль Англіі)BG: Джеймс I (Англия)CA: Jaume I d'AnglaterraCS: Jakub I. StuartDA: Jakob 6. af Skotland og 1. af EnglandDE: Jakob I. (England)EL: Ιάκωβος Α΄ και ΣΤ΄ της Αγγλίας και της ΣκωτίαςEN: James VI and IEO: Jakobo la 1-a (Anglio)ES: Jacobo I de Inglaterra y VI de EscociaET: James VI ja IEU: Jakue I.a IngalaterrakoaFA: جیمز یکم (انگلستان)FI: Jaakko I (Englanti)FR: Jacques VI et IerGL: Xacobe VI de Escocia e I de InglaterraHE: ג'יימס הראשון, מלך אנגליהHI: जेम्स प्रथमHR: Jakov I., kralj EngleskeHU: I. Jakab angol királyHY: Հակոբ ԱID: James Charles StuartIT: Giacomo I d'InghilterraJA: ジェームズ1世 (イングランド王)KA: ჯეიმზ I (ინგლისი)KO: 제임스 1세 (잉글랜드)LA: Iacobus I (rex Angliae)LT: Jokūbas VIMS: James VI dan INL: Jacobus I van EngelandNN: Jakob VI av Skottland og I av EnglandNO: Jakob I av EnglandPL: Jakub I StuartPT: Jaime VI da Escócia e I de InglaterraRO: Iacob I al AnglieiRU: Яков I (король Англии)SH: James I StuartSIMPLE: James I of EnglandSK: Jakub I. (Anglicko)SL: Jakob I. AngleškiSR: Џејмс I СтјуартSV: Jakob I av EnglandTA: இங்கிலாந்தின் முதலாம் ஜேம்சுTH: พระเจ้าเจมส์ที่ 1 แห่งอังกฤษTR: I. James (İngiltere kralı)UK: Яків I (король Англії)UR: جیمز ششم اور اولVI: James VI và I của AnhZH: 詹姆士六世及一世ZHMINNAN: James 1-sè

Normalized quality metrics

Languages comparsion

Cumulative results

About WikiRank

The project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 38 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from March, 2019. When calculating popularity, view statistics of articles for last month (February 2019) were taken into account.

You can also visit WikiRank.Live (previous version of the main tool), which can calculate quality and popularity based on current versions of Wikipedia articles in 7 languages.

It's planned to add different improvements to the project (such as adding to the analysis not only new quantitative characteristics, but also qualitative). In addition, it is planned to add estimates using machine learning algorithms and artificial intelligence, as well as based on the results of user comparison of specific multilingual information (for example, the WikiBest project). Please leave your comments and suggestions

More information about quality assessment of Wikipedia articles and project WikiRank can be found in scientific publications:

Additional information about quality issues can be found on Wikipedia Quality portal.

WikiRank video

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Quality and popularity formulas for the article James I of England SIMPLE

$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(21.73+1.96+25+11.11+9.13)$$

where:

$$Popularity={tp(l)}/{tp(l^'_{tp})}×50+{sp(l)}/{sp(l^'_{sp})}×50=5195/73481×50+197/2543×50$$

where:

The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas