Dutch football play-offs 2019 - Play-offs for a 2nd round UEFA Europa League berth and for promotion/relegation between the Eredivisie and the Eerste Divisie. Article "Play-offs Nederlands voetbal 2019" in Dutch Wikipedia has 28.7 points for quality (as of November 1, 2023). The article contains 8 references and 12 sections.
In October 2023 the article "Play-offs Nederlands voetbal 2019" was edited by 1 authors in Dutch Wikipedia and written by 1 authors in all languages.
Since the creation of article "Play-offs Nederlands voetbal 2019", its content was written by 8 registered users of Dutch Wikipedia and edited by 8 registered Wikipedia users in all languages.
The article is cited 63 times in Dutch Wikipedia and cited 63 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from November 1, 2023 (including revision history and pageviews for previous years).
| Best Rank | Dutch: #286 05.2019 |
Global: #123848 05.2019 |
| Best Rank | Dutch: #1382 05.2019 |
Global: #227946 05.2019 |
On 14 April 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: Iran, Bayer 04 Leverkusen, Israel, Fallout, Iron Dome, Xabi Alonso, Max Holloway, Fallout, YouTube, Bundesliga.
In Dutch Wikipedia the most popular articles on that day were: Iran, Bayer 04 Leverkusen, Abdi Nageeye, Amstel Gold Race, Lee Towers, IJzeren Koepel, Israël, Marianne Vos, Leverkusen, XXXX.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from November, 2023. When calculating current popularity and AI of articles data from October 2023 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(53.41+14.04+0+52.17+24.12)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
