Karlo I., kralj Engleske

HR

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Karlo I., kralj Engleske

Article "Karlo I., kralj Engleske" in Croatian Wikipedia has 36.911 points for quality and 0.1309 points for popularity. The article contains, among others metrics, 1 references and 12 sections.

This article has the best quality in English Wikipedia. Also, this article is the most popular in that language version.

There are 53 language versions for this article in WikiRank database (of the considered 55 Wikipedia language editions).

Data as of November 1, 2018. Query time 0.1083 sec.

The table below shows the language versions of the article with the highest quality.

Languages with the highest quality

#LanguageQuality gradeQuality score
1English
Charles I of England
100
2Portuguese
Carlos I de Inglaterra
100
3Chinese
查理一世 (英格蘭)
100
4Vietnamese
Charles I của Anh
100
5Greek
Κάρολος Α΄ της Αγγλίας
100

The following table shows the most popular language versions of the article.

The most popular languages

#LanguagePopularity gradePopularity score
1English
Charles I of England
100
2Russian
Карл I (король Англии)
9.8692
3Spanish
Carlos I de Inglaterra
8.9099
4German
Karl I. (England)
5.8938
5French
Charles Ier (roi d'Angleterre)
5.8231

Scores

Quality:
Popularity:

Interwiki

AR: تشارلز الأول ملك إنجلتراAZ: I Karl (İngiltərə kralı)BE: Карл I СцюартBG: Чарлз ICA: Carles I d'AnglaterraCS: Karel I. StuartDA: Karl 1. af EnglandDE: Karl I. (England)EL: Κάρολος Α΄ της ΑγγλίαςEN: Charles I of EnglandEO: Karlo la 1-a (Anglio)ES: Carlos I de InglaterraET: Charles IEU: Karlos I.a Ingalaterrakoa eta EskoziakoaFA: چارلز یکم انگلستانFI: Kaarle I (Englanti)FR: Charles Ier (roi d'Angleterre)GL: Carlos I de InglaterraHE: צ'ארלס הראשון, מלך אנגליהHI: चार्ल्स १HR: Karlo I., kralj EngleskeHU: I. Károly angol királyHY: Չարլզ I ՍտյուարտID: Charles I dari InggrisIT: Carlo I d'InghilterraJA: チャールズ1世 (イングランド王)KA: ჩარლზ IKK: Карл IKO: 찰스 1세LA: Carolus I (rex Angliae)LT: Karolis I (Anglija)MS: Charles I dari EnglandNL: Karel I van EngelandNN: Karl I av EnglandNO: Karl I av EnglandPL: Karol I StuartPT: Carlos I de InglaterraRO: Carol I al AnglieiRU: Карл I (король Англии)SH: Charles I StuartSIMPLE: Charles I of EnglandSK: Karol I. (Anglicko)SL: Karel I. AngleškiSR: Чарлс I СтјуартSV: Karl I av EnglandTA: இங்கிலாந்தின் முதலாம் சார்லசுTH: พระเจ้าชาลส์ที่ 1 แห่งอังกฤษTR: I. Charles (İngiltere kralı)UK: Карл I (король Англії)UR: چارلس اول شاہ انگلستانVI: Charles I của AnhZH: 查理一世 (英格蘭)ZHMINNAN: Charles 1-sè (Eng-lân)

Normalized quality metrics

Languages comparsion

Cumulative results

About WikiRank

The project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 38 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from November, 2018. When calculating popularity, view statistics of articles for last year (from 1 November 2017 to 31 October 2018) were taken into account.

You can also visit WikiRank.Live (previous version of the main tool), which can calculate quality and popularity based on current versions of Wikipedia articles in 7 languages.

It's planned to add different improvements to the project (such as adding to the analysis not only new quantitative characteristics, but also qualitative). In addition, it is planned to add estimates using machine learning algorithms and artificial intelligence, as well as based on the results of user comparison of specific multilingual information (for example, the WikiBest project). Please leave your comments and suggestions

The WikiRank project was developed on the basis of researches made by scientists from Poland and Belarus. More information about quality assessment of Wikipedia articles and project WikiRank can be found in scientific publications:

Additional information about quality issues can be found on Wikipedia Quality portal.

WikiRank video

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Quality and popularity formulas for the article Karlo I., kralj Engleske HR

$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(53.11+3.92+50+70.59+6.94)$$

where:

$$Popularity={tp(l)}/{tp(l^'_{tp})}×50+{sp(l)}/{sp(l^'_{sp})}×50=1601/947311×50+2/2156×50$$

where:

The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas